Jrue Holiday is heading to Milwaukee. Pool Photo-USA TODAY Sports

Full details of four-team Jrue Holiday trade released

By Erin Walsh | Last updated 11/22/20

The Milwaukee Bucks are acquiring Jrue Holiday in a four-team trade with the New Orleans Pelicans. News of the trade surfaced over the past week, but now we know the full details.

Shams Charania of The Athletic has the full details below, which includes Steven Adams being shipped to New Orleans:

Trade complete:

MIL: Jrue Holiday, No. 60 pick Sam Merrill
NOLA: Steven Adams, Eric Bledsoe, ‘25/'27 1sts, ‘24/'26 swaps via MIL
OKC: George Hill, Josh Gray, Kenrich Williams, Zylan Cheatham, Darius Miller, ‘23 protected 1st via Denver, two 2nd round picks
DEN: RJ Hampton
— Shams Charania (@ShamsCharania) November 22, 2020

Holiday joins a team in Milwaukee that has been rather aggressive in the free-agent market this offseason. The Bucks also have added Bryn Forbes, Torrey Craig, D.J. Augustin and Bobby Portis on top of re-signing Pat Connaughton. They tried to land Bogdan Bogdanovic, but the sign-and-trade deal with the Sacramento Kings was botched because the Serbian never agreed to it.

Adams, meanwhile, will replace Derrick Favors in New Orleans and Hill heads to a rebuilding Thunder team.

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